The area (in sq.units) of the region bounded by the parabolas $y^2=4 x$ and $y^2=4(4-x)$ is

• A

  $\frac{7}{4}-\sqrt{2}$
• B

  $2(\sqrt{2}-1)$
• Correct answer
  C

  $\frac{32 \sqrt{2}}{3}$
• D

  $\frac{8}{3}$

Hence, the correct answer is option: 'C'.