The area (in sq. units) bounded by the curve $e^{x}y-2=0$ with the $x$-axis from $x=0$ to $x=\ln 2$ is

Solution

The required area is $A=\underset{0}{\overset{\ln 2}{\int }}\left(2e^{-x}\right)dx$
$=\left[-2e^{-x}\right]\begin{array}{c}\ln 2\\ 0\end{array}$
$=\left(-2\right)\left[e^{-\ln 2}-e^0\right]$
$=\left(-2\right)\mathrm{}\left[\frac{1}{2}-1\right]$
$=1$ sq. units

Hence, the correct answer is 1.