Q31 / 90 · NTA Abhyas (JEE Main) 2020 · Mathematics · Area Under Curves

The area (in sq. units) bounded by the curve $y = \{\begin{cases} x & : & x \in [0,1] \\ 2 - x & : & x \in [1,2] \end{cases}$ with the $x$ -axis from $x = 0$ to $x = 2$ is

A
$2$
B
$\frac{1}{2}$
Correct answer
C
$1$
D
$4$

Solution

The required area

= \frac{1}{2} \cdot 2 \cdot 1 = 1

sq. units

Hence, the correct answer is option: 'C'.

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