The angular width of a fringe in a double slit experiment is found to be 0.2° on a screen 1 m away. The wavelength of light used is 600 nm. The change…

Question

The angular width of a fringe in a double slit experiment is found to be 0.2° on a screen 1 m away. The wavelength of light used is 600 nm. The change in angular width of the fringe if the entire measurement system is immersed in water is [Use refractive index of water as 4/3]

MARKS Content Team · Accepted Answer

Correct answer: (A) 0.05°. Wavelength of light in a denser medium will decrease. So, λ_2=λ_1μ=λ_14/3=3/4 Angular fringe width is given by, β_(θ)=(λ)/d⇒β_(θ)∝λ Therefore, β_(θ,1)β_(θ,2)=λ_1λ_2⇒β_(θ,2)=(λ_2)/(λ_1)×β_(θ,1)=3/4×0.2°=0.15° Hence, change in angular frigne width =0.2°-0.15°=0.05°

The angular width of a fringe in a double slit experiment is found to be $0.2 °$ on a screen $1 m$ away. The wavelength of light used is $600 nm$ . The change in angular width of the fringe if the entire measurement system is immersed in water is [Use refractive index of water as $\frac{4}{3}$ ]

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Relevant Questions

The angular width of a fringe in a double slit experiment is found to be 0.2° on a screen 1 m away. The wavelength of light used is 600 nm. The change in angular width of the fringe if the entire measurement system is immersed in water is [Use refractive index of water as 43]

Solution

Relevant Questions

The angular width of a fringe in a double slit experiment is found to be $0.2 °$ on a screen $1 m$ away. The wavelength of light used is $600 nm$ . The change in angular width of the fringe if the entire measurement system is immersed in water is [Use refractive index of water as $\frac{4}{3}$ ]