Q138 / 200 · NEET 2005 · Physics

The angular resolution of a $10 \mathrm{~cm}$ diameter telescope at a wavelength of $5000 Å$ is of the order of:

  • A
    $10^6 \mathrm{rad}$
  • B
    $10^{-2} \mathrm{rad}$
  • C
    $10^{-4} \mathrm{rad}$
  • Correct answer
    D
    $10^{-6} \mathrm{rad}$

Solution

Here $R \cdot P .=\frac{1}{\Delta \theta}$ $$ \begin{aligned} & \therefore \text { Angular resolution } \Delta \theta=\frac{1.22 \lambda}{\mathrm{D}} \\ &=\frac{1.22 \times 5000 \times 10^{-10}}{0.1} \\ &=6.10 \times 10^{-6} \\ & \cong 10^{-6} \end{aligned} $$

Hence, the correct answer is option: 'D'.

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