Q158 / 160 · AP EAMCET 2021 (20 Aug Shift 1) · Physics

The angular momentum of the orbital electron is integral multiple of:

A
$h$
B
$2 π h$
Correct answer
C
$\frac{h}{2 π}$
D
$3 π h$

Solution

According to Bohr''s second postulate, an electron can only revolve in those nuclear orbits of principal quantum numbers ''n'' which have angular momentum value as equal to integral multiples of $\frac{h}{2 π} .$

Therefore, $m v r = \frac{n h}{2 π}$

Hence, the correct answer is option: 'C'.

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