The $\mathrm{P}-\mathrm{P}-\mathrm{P}$ angle in $\mathrm{P}_{4}$ molecule and $\mathrm{S}-\mathrm{S}-\mathrm{S}$ angle in $\mathrm{S}_{8}$ molecule is(in degree) respectively

• Correct answer
  A

  $60^{\circ}, 107^{\circ}$
• B

  $107^{\circ}, 60^{\circ}$
• C

  $40^{\circ}, 60^{\circ}$
• D

  $60^{\circ}, 40^{\circ}$

Solution

In $P_{4}$ molecule, the four sp $^{3}$ -hybridised phosphorous atoms lie at the corners of a regular tetrahedron with $\angle \mathrm{PPP}=60^{\circ}$. In $\mathrm{S}_{8}$ molecule S-S-S angle is $107^{\circ}$ rings. In $\mathrm{S}_{8}$ molecule $\mathrm{S}-\mathrm{S}-\mathrm{S}$ angle is $107^{\circ} \mathrm{rings} .$

Hence, the correct answer is option: 'A'.