The angle between the pair of tangents drawn to the ellipse 3x^2 +2y^2 =5 from the point 1, 2 is tan^(−1) 12/(√(λ)) , then the value of λ is

Question

MARKS Content Team · Accepted Answer

Correct answer: 5. Equation of pair of tangents 3x^2 +2y^2 −5 6 =3x+4y−5^2 9x^2 −4y^2 −24xy+30x+40y−55=0 tanθ=12/(√5)

The angle between the pair of tangents drawn to the ellipse $3 x^{2} + 2 y^{2} = 5$ from the point $(1, 2)$ is $|\tan^{- 1} (\frac{12}{\sqrt{λ}})|,$ then the value of $λ$ is