Q47 / 250 · NTA Abhyas (NEET) 2020 · Physics · Electrostatics

The amount of work done in moving a charge of $5 C$ across two points having a potential difference of $15$ Volts is equal to

A
$0.333 J$
B
$3 J$
C
$6 J$
Correct answer
D
$75 J$

Solution

Work done

=

(charge)

\times

(potential difference)

W = q (Δ V) = 5 \times 15 = 75 J

Hence, the correct answer is option: 'D'.

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