Q112 / 180 · NEET 2013 (All India) · Physics
The amount of heat energy required to raise the temperature of 1 g of helium at NTP, from $T_1 \mathrm{~K}$ to $T_2 \mathrm{~K}$ is
- Correct answerA$\frac{3}{8} N_2 K_B\left(T_2-T_1\right)$
- B$\frac{3}{2} N_2 K_B\left(T_2-T_1\right)$
- C$\frac{3}{4} N_2 K_B\left(T_2-T_1\right)$
- D$\frac{3}{4} N_2 K_B\left(\frac{T_2}{T_1}\right)$
Solution
We know that $Q=\frac{F}{2} n R \Delta T$
$\therefore$ Amount of heat required,
$\begin{aligned}
Q & =\frac{3}{2} \times \frac{1}{4} \times K_B N_B \Delta T \\
& =\frac{3}{8} N_B K_B\left(T_2-T_1\right)
\end{aligned}$
Hence, the correct answer is option: 'A'.