Q105 / 180 · JIPMER 2015 · Physics

The ammeter shown in figure consists of a $480 \Omega$ coil connected in parallel to a $20 \Omega$ shunt. The reading of ammeter is Figure

  • Correct answer
    A
    0.125 A
  • B
    1.67 A
  • C
    0.13 A
  • D
    0.67 A

Solution

The equivalent resistance of the ammeter is $\frac{(480)(20)}{480+20}=19.2 \Omega$ The equivalent resistance of the circuit is $1408+19.2 \Omega=160 \Omega$ The current, $i=\frac{20 \mathrm{~V}}{160 \Omega}=0.125 \mathrm{~A}$ Hence, ammeter reading is 0.125 A .

Hence, the correct answer is option: 'A'.

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