The ammeter reading in the given circuit is

• A

  $\frac{14}{33}\mathrm{ }\mathrm{A}$
• Correct answer
  B

  $\frac{15}{32}\mathrm{ }\mathrm{A}$
• C

  $\frac{17}{33}\mathrm{ }\mathrm{A}$
• D

  $\frac{15}{31}\mathrm{A}$

Solution

$\mathrm{E}{}_{\mathrm{e}\mathrm{q}}=\frac{3\times 1+6\times 2}{1+2}=5\mathrm{V},\mathrm{ }{\mathrm{r}}_{\mathrm{e}\mathrm{q}}=\frac{2\times 1}{2+1}=\frac{2}{3}\mathrm{\Omega }$








$\mathrm{I}=\frac{5}{10+2/3}=\frac{15}{32}\mathrm{ }\mathrm{A}$

Hence, the correct answer is option: 'B'.