Q15 / 199 · NTA Abhyas (NEET) 2020 · Physics · Nuclear Physics

The activity of a sample of radioactive material is A1 at time t1 and A2 at time t2t2>t1 . Its mean life is T. Which of the following is correct?

  • A
    A1t1=A2t2
  • B
    A1+A2t2–t1= constant
  • Correct answer
    C
    A2=A1et1–t2T
  • D
    A2=A1et1Tt2

Solution

We know that for time t1 activity is A1 , therefore A1=A0e–t1T .....(1)

Similarly for time t2 activity is A2 , Therefore A2=A0e–t2T ......(2)

Now, dividing equation (1) by (2) A1A2=et2–t1T

Therefore, A2=A1et1–t2T

Hence, the correct answer is option: 'C'.

More Nuclear Physics Questions