The acid in which $\mathrm{O}-\mathrm{O}$ bonding is present is

• A

  $\mathrm{H}_{2} \mathrm{S}_{2} \mathrm{O}_{3}$
• B

  $\mathrm{H}_{2} \mathrm{S}_{2} \mathrm{O}_{6}$
• Correct answer
  C

  $\mathrm{H}_{2} \mathrm{S}_{2} \mathrm{O}_{8}$
• D

  $\mathrm{H}_{2} \mathrm{S}_{4} \mathrm{O}_{6}$

Solution

$\mathrm{H}_{2} \mathrm{S}_{2} \mathrm{O}_{8}$ shows $-\mathrm{O}-\mathrm{O}-$ (peroxy) bonding as follows:

Hence, the correct answer is option: 'C'.