Q59 / 59 · KVPY 2013 (SA) · Physics
The accompanying graph of position $x$ versus time $t$ represents the motion of a particle. If $p$ and $q$ are both positive constants, the expression that best describes the acceleration $\alpha$ of the particle is
- A$\mathrm{a}=-\mathrm{p}-\mathrm{qt}$
- B$a=-p+q t$
- C$\mathrm{a}=\mathrm{p}+\mathrm{qt}$
- Correct answerD$a=p-q t$
Solution
From graph $\mathrm{V}$ first increases then decreases
Hence $\mathrm{a}$ is earliar positive then negative
$\mathrm{a=P-q t}$
Hence, the correct answer is option: 'D'.