Q121 / 180 · COMEDK 2024 (Memory Based) · Physics

The acceleration of a train between two stations is shown in the figure. The maximum speed of the train is
Figure

  • A
    $60 \mathrm{~m} / \mathrm{s}$
  • Correct answer
    B
    $30 \mathrm{~m} / \mathrm{s}$
  • C
    $120 \mathrm{~m} / \mathrm{s}$
  • D
    $90 \mathrm{~m} / \mathrm{s}$

Solution

$\begin{aligned}<br/>& v_{\max }=\text { Maximum positive area of } a-t \text { graph } \\<br/>& =\text { area between } 0 \text { and } 8 \mathrm{~s} \\<br/>& \text { Area of triangle }+ \text { Area of rectangle }=\frac{1}{2} \times 4 \times 5+4 \times 5 \\<br/>& =30 \mathrm{~m} / \mathrm{s}<br/>\end{aligned}$

Hence, the correct answer is option: 'B'.

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