Q26 / 180 · KCET 2023 · Chemistry
Temperature of $25^{\circ} \mathrm{C}$ in Fahrenheit and Kelvin scale respectively are
- Correct answerA$77^{\circ} \mathrm{F}$ and $298.15 \mathrm{~K}$
- B$17^{\circ} \mathrm{F}$ and $298.15 \mathrm{~K}$
- C$45^{\circ} \mathrm{F}$ and $260.15 \mathrm{~K}$
- D$47^{\circ} \mathrm{F}$ and $312.15 \mathrm{~K}$
Solution
$\mathrm{F}=\frac{9}{5}^{\circ} \mathrm{C}+32$
$=\frac{9}{5}(25)+32=77^{\circ} \mathrm{F}$
$\mathrm{K}=273.15+{ }^{\circ} \mathrm{C}=273.15+25=298.15 \mathrm{~K}$
Hence, the correct answer is option: 'A'.