Q153 / 160 · TS EAMCET 2007 · Physics
Temperature of cold junction in a thermocouple is $10^{\circ} \mathrm{C}$ and neutral temperature is $270^{\circ} \mathrm{C}$, then the temperature of inversion is
- A$540^{\circ} \mathrm{C}$
- Correct answerB$530^{\circ} \mathrm{C}$
- C$280^{\circ} \mathrm{C}$
- D$260^{\circ} \mathrm{C}$
Solution
Temperature of inversion is
$\begin{aligned} & T_i=2 T_n-T_0 \\ & \therefore \quad T_i=2 \times 270-10=530^{\circ} \mathrm{C} \\ & \end{aligned}$
Hence, the correct answer is option: 'B'.