(tan^(-1)⁡√3-sec^(-1)⁡-2)/(cosec⁡^(-1)-√2+cos^(-1)⁡-12)=

Correct answer: (B) -4/5. By solving we will get, (tan^(-1)⁡ √3-sec^(-1)⁡ -2)/(cosec^(-1)⁡ -√2+cos^(-1)⁡ -12)= (π)/3-(2π)/3-(π)/4+(2π)/3=(-π)/3(5π)/12= -4/5

Q69 / 150 · MHT CET 2016 · Mathematics

$\frac{\tan^{- 1} (\sqrt{3}) - \sec^{- 1} (- 2)}{cosec^{- 1} (- \sqrt{2}) + \cos^{- 1} (- \frac{1}{2})} =$

A
$\frac{4}{5}$
Correct answer
B
$- \frac{4}{5}$
C
$\frac{3}{5}$
D
$0$

Solution

By solving we will get,

\frac{\tan^{- 1} (\sqrt{3}) - \sec^{- 1} (- 2)}{\cos e c^{- 1} (- \sqrt{2}) + \cos^{- 1} (- \frac{1}{2})} =

\frac{\frac{π}{3} - \frac{2 π}{3}}{- \frac{π}{4} + \frac{2 π}{3}} = \frac{- \frac{π}{3}}{\frac{5 π}{12}} = - \frac{4}{5}

Hence, the correct answer is option: 'B'.

tan-1⁡3-sec-1⁡-2cosec⁡-1-2+cos-1⁡-12=

Solution

Relevant Questions

$\frac{\tan^{- 1} (\sqrt{3}) - \sec^{- 1} (- 2)}{cosec^{- 1} (- \sqrt{2}) + \cos^{- 1} (- \frac{1}{2})} =$