Suppose that p→, q→ and r→ are three non - coplanar vectors in R^3 . Let the components of a vector s→ along p, q and r be 4,3 and 5 respectively. If…

Question

Suppose that p→, q→ and r→ are three non - coplanar vectors in R^3 . Let the components of a vector s→ along p, q and r be 4,3 and 5 respectively. If the components of -p→+ q→+ r→, p→- q→+ r→ and - p→- q→+ r→ are x, y and z, respectively, then the value of 2x+y+z is

MARKS Content Team · Accepted Answer

Correct answer: 9. This question is seem to be wrong but may be taken as S→=x-p→+q→+r→+yp→-q→+r→+z-p→-q→+r→ -x+y-z=4 ..... (i) x-y-z=3 ...... (ii) x+y+z=5 ..... (iii) Add (i) and (ii) -2z=7⇒z=-7/2 2x=8⇒x=4 2x+y+z=24+1=9

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Suppose that p→, q→ and r→ are three non - coplanar vectors in R3 . Let the components of a vector s→ along \(p, q\) and \(r\) be 4,3 and 5 respectively. If the components of -p→+ q→+ r→, p→- q→+ r→ and - p→- q→+ r→ are x, y and z, respectively, then the value of 2x+y+z is

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