Q62 / 125 · BITSAT 2019 · Mathematics

Suppose a parabola y=ax2+bx+c has two x intercepts, one positive and one negative, and its vertex is (2,-2), then which of the following is true?

  • A
    ab>0
  • Correct answer
    B
    bc>0
  • C
    ac>0
  • D
    a+b+c>0

Solution

Given, y=ax2+bx+c has two x-intercepts one is positive and one is negative and vertex is (2,-2). The graph of y=ax2+bx+c is

Figure

Clearly from graph

c>0

-ba>0⇒-b>0

⇒ b<0

f(1)=a+b+c<0

ab<0,ac<0,bc>0

Hence, the correct answer is option: 'B'.

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