Suppose a long rectangular loop o width w is moving along the x-direction with its left arm in magnetic field perpendicular to the plane of the loop…

Question

Suppose a long rectangular loop o width $w$ is moving along the $x$ -direction with its left arm in magnetic field perpendicular to the plane of the loop (see figure). The resistance of the loop is zero and it has an inductance $L .$ At time, $t = 0,$ its left arm passes the origin, $O .$

If for $t \geq 0,$ the current in the loop is $I$ and the distance of its left arm from the origin is $x,$ then $I$ versus $x$ garph will be

MARKS Content Team · Accepted Answer

Correct answer: (B). VBℓ-Ldi/dt=0 VBℓ=Ldi/dt ⇒di/dt=(VBℓ)/L =+ve slope x=ut⇒dx/dt=V di/dx=(Bℓ)/L=+ve slope

Solution

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