Sulphide ore on roasting gives a gas $X . X$ reacts with $\mathrm{Cl}_{2}$ in the presence of activated charcoal to give $Y$. $Y$ is

• Correct answer
  A

  $\mathrm{SO}_{2} \mathrm{Cl}_{2}$
• B

  $\mathrm{S}_{2} \mathrm{Cl}_{2}$
• C

  $\mathrm{SCl}_{6}$
• D

  $\mathrm{SOCl}_{2}$

Solution

When sulphite ore is roasted it means that sulphide ore is being heated in the presence of excess of air to form a gas $\mathrm{SO}_{2}$. $\underset{\text { From sulphide ore) }}{\mathrm{S}}+\mathrm{O}_{2} \longrightarrow \underset{(X)}{\mathrm{SO}_{2}}$ e.g. $\quad 2 \mathrm{ZnS}+3 \mathrm{O}_{2} \longrightarrow 2 \mathrm{ZnO}+2 \mathrm{SO}_{2}$ Thereafter, $X$ reacts with $\mathrm{Cl}_{2}$ in the presence of activated charcoal to give $Y$

Hence, the correct answer is option: 'A'.