Student A and student B used two screw gauges of equal pitch and 100 equal circular divisions to measure the radius of a given wire. The actual value…

Question

Student A and student B used two screw gauges of equal pitch and 100 equal circular divisions to measure the radius of a given wire. The actual value of the radius of the wire is 0.322 cm. The absolute value of the difference between the final circular scale readings observed by the students A and B is _______. [Figure shows position of reference O when jaws of screw gauge are closed] Given pitch =0.1 cm.

MARKS Content Team · Accepted Answer

Correct answer: 13. For A, Reading =MSR+CSR+Error 0.322=0.300+CSR+5×LC 0.322=0.300+CSR+0.005 CSR=0.017 For B, Reading =MSR+CSR+Error 0.322=0.200+CSR+0.092 CSR=0.030 Difference =0.030-0.017=0.013 cm Division on circular scale =0.013/0.001=13

Solution

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