Strength of H_2 O_2 is 15.18 ~g ~L^-1 , then it is equal to

Correct answer: (C) 5 volume. Volume strength =frac5.6 × Strength in g L^-1 Eq. wt. of H_2 O_2 =(5.6 × 15.18)/17=5 volumes

Q60 / 180 · AIIMS 2013 · Chemistry

Strength of $\mathrm{H}_2 \mathrm{O}_2$ is $15.18 \mathrm{~g} \mathrm{~L}^{-1}$, then it is equal to

A
1 volume
B
10 volume
Correct answer
C
5 volume
D
7 volume

Solution

Volume strength $=\frac{5.6 \times \text { Strength in } \mathrm{g} \mathrm{L}^{-1}}{\text { Eq. wt. of } \mathrm{H}_2 \mathrm{O}_2}$ $=\frac{5.6 \times 15.18}{17}=5$ volumes

Hence, the correct answer is option: 'C'.

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