Q35 / 54 · KVPY 2017 (5 Nov SA) · Physics
Stoke's law states that the viscous drag force $F$ experienced by a sphere of radius a, moving with a speed $V$ through a fluid with coefficient of viscosity $\eta$, is given by $F=6$ inav. If this fluid is flowing through a cylindrical pipe of radiusr, leng th $/$ and a pressure difference of Pacross its two ends, then the volume of water $V$ which
flows through the pipe in time $t$ can be written as $\frac{V}{t}=k\left(\frac{P}{\ell}\right)^{a} \eta^{b} r^{c}$, where $k$ is a dimensional constant. Correct values of $a, b$ and $c$ are
- Correct answerA$a=1, b=-1, c=4$
- B$a=-1, b=1, c=4$
- C$a=2, b=-1, c=3$
- D$a=1, b=-2, c=-4$
Solution
$\begin{array}{l}
\frac{V}{t}=k\left(\frac{P}{\ell}\right)^{a} \cdot \eta^{b} \cdot \gamma^{c} \\
{[r]=L ;[l]=L} \\
{[P]=M L^{-1} T^{-2} ;[\eta]=M L^{-1} T^{-1}} \\
{[\mathrm{~V}]=L^{3}} \\
{[t]=T}
\end{array}$
By calculation
$a=1 ; b=-1 ; c=4$
Hence, the correct answer is option: 'A'.