Q50 / 90 · JEE Main 2012 (19 May Online) · Mathematics

Statement 1: The shortest distance between the lines $\frac{x}{2}=\frac{y}{-1}=\frac{z}{2}$ and $\frac{x-1}{4}=\frac{y-1}{-2}=\frac{z-1}{4}$ is $\sqrt{2}$. Statement 2: The shortest distance between two parallel lines is the perpendicular distance from any point on one of the lines to the other line.

  • A
    Statement 1 is true, Statement 2 is false.
  • B
    Statement 1 is true, Statement 2 is true, Statement 2 is a correct explanation for Statement 1.
  • Correct answer
    C
    Statement 1 is false, Statement 2 is true.
  • D
    Statement 1 is true, Statement 2 is true, , Statement 2 is not a correct explanation for Statement 1.

Solution

On solving we will get shortest distance $$ \neq \sqrt{2} $$

Hence, the correct answer is option: 'C'.

Relevant Questions