Q50 / 90 · JEE Main 2012 (19 May Online) · Mathematics
Statement 1: The shortest distance between the lines $\frac{x}{2}=\frac{y}{-1}=\frac{z}{2}$ and $\frac{x-1}{4}=\frac{y-1}{-2}=\frac{z-1}{4}$ is $\sqrt{2}$.
Statement 2: The shortest distance between two parallel lines is the perpendicular distance from any point on one of the lines to the other line.
- AStatement 1 is true, Statement 2 is false.
- BStatement 1 is true, Statement 2 is true, Statement 2 is a correct explanation for Statement 1.
- Correct answerCStatement 1 is false, Statement 2 is true.
- DStatement 1 is true, Statement 2 is true, , Statement 2 is not a correct explanation for Statement 1.
Solution
On solving we will get shortest distance
$$
\neq \sqrt{2}
$$
Hence, the correct answer is option: 'C'.