Q45 / 180 · AIIMS 2001 · Chemistry

Smallest intermolecular distance is found in

  • A
    $\mathrm{O}_2$
  • Correct answer
    B
    $\mathrm{O}_2^{+}$
  • C
    $\mathrm{O}_2^{-}$
  • D
    $\mathrm{O}_2^{2-}$

Solution

In $\mathrm{O}_2$, the bond order $=2$ In $\mathrm{O}_2^{+}$, the bond order $=2.5$ In $\mathrm{O}_2^{-}$, the bond order $=1.5$ In $\mathrm{O}_2^{-2}$, the bond order $=1$ As the bond order in $\mathrm{O}_2^{+}$is highest, so its internuclear distance is smallest.

Hence, the correct answer is option: 'B'.

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