Q99 / 180 · AIIMS 2003 · Physics

Shown below are the black body radiation curves at temperatures $T_1$ and $T_2\left(T_2>T_1\right)$. Which of the following plots is correct?

  • A
    Figure
  • B
    Figure
  • Correct answer
    C
    Figure
  • D
    Figure

Solution

From Wien's displacement law, we know that, $\lambda_m T=$ constant which means that as temperature increases then the wavelength having the maximum intensity shifts towards left. Here, $T_2>T_1$. $$ \therefore \quad \lambda_{m_{T_2}} < \lambda_{m_{T_1}} $$ But in plot (a) $\lambda_{m_{T_2}}=\lambda_{m_{T 1}}$, in plot (b) $\lambda_{m_{T_2}}>\lambda_{m_{T_1}}$ and in plot (d) $\lambda_{m_{T_2}}>\lambda_{m_{\overparen{1}}}$. Therefore the correct plot is (c) where $\lambda_{m_{T_2}} < \lambda_{m_{T_1}}$.

Hence, the correct answer is option: 'C'.

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