$\mathrm{z}_1, \mathrm{z}_2, \mathrm{z}_3$ represent the vertices $\mathrm{A}, \mathrm{B}, \mathrm{C}$ of a triangle ABC respectively in the Argand plane. If $\left|z_1-z_2\right|=\sqrt{25-12 \sqrt{3}},\left|\frac{z_1-z_3}{z_2-z_3}\right|=\frac{3}{4}$ and $\underline{\mathrm{ACB}}=30^{\circ}$, then the area (in sq. units) of that traingle is

• A

  $\frac{3}{2}$
• Correct answer
  B

  $3$
• C

  $5$
• D

  $\frac{5}{2}$

Hence, the correct answer is option: 'B'.