Reduction of nitrobenzene in the presence of $\mathrm{Zn} / \mathrm{NH}_4 \mathrm{Cl}$ gives

• A

  azobenzene
• B

  hydrazobenzene
• Correct answer
  C

  N-phenyl hydroxyl amine
• D

  aniline

Solution

Reduction of nitrobenzene by Zn and $\mathrm{NH}_4 \mathrm{Cl}$ gives N-phenyl hydroxylamine.

Hence, the correct answer is option: 'C'.