$\mathrm{H}_2 \mathrm{O}_2$ reduces $\mathrm{KMnO}_4$ in acidic medium to ' $x$ ' and in basic medium to ' $y$ '. What are $x$ and $y$ ?

• A

  $x=\mathrm{MnO}_2, \quad y=\mathrm{Mn}^{2+}$
• Correct answer
  B

  $x=\mathrm{Mn}^{2+}, \quad y=\mathrm{MnO}_2$
• C

  $x=\mathrm{MnO}_4^{2-}, y=\mathrm{Mn}^{2+}$
• D

  $x=\mathrm{MnO}_2, \quad y=\mathrm{MnO}_4^{2-}$

Hence, the correct answer is option: 'B'.