LiOH reacts with CO_2 to form Li_2 CO_3 (atomic mass of Li=7 ). The amount of CO_2 (in g) consumed by 1 ~g of LiOH is closest to

Correct answer: (A) 0.916. 2 LiOH+CO_2 longrightarrow Li_2 CO_3+H_2 O 1/24 1/(24 × 2) No. of moles of CO_2=1/48 mass of CO_2=1/48 × 44=0.916 ~g

Q5 / 58 · KVPY 2016 (SA) · Chemistry

$\mathrm{LiOH}$ reacts with $\mathrm{CO}_{2}$ to form $\mathrm{Li}_{2} \mathrm{CO}_{3}$ (atomic mass of $\mathrm{Li}=7$ ). The amount of $\mathrm{CO}_{2}$ (in g) consumed by $1 \mathrm{~g}$ of LiOH is closest to

Correct answer
A
$0.916$
B
$1.832$
C
$0.544$
D
$1.088$

Solution

$\begin{array}{l} 2 \mathrm{LiOH}+\mathrm{CO}_{2} \longrightarrow \mathrm{Li}_{2} \mathrm{CO}_{3}+\mathrm{H}_{2} \mathrm{O} \\ \frac{1}{24} \frac{1}{24 \times 2} \end{array}$ No. of moles of $\mathrm{CO}_{2}=\frac{1}{48}$ mass of $\mathrm{CO}_{2}=\frac{1}{48} \times 44=0.916 \mathrm{~g}$

Hence, the correct answer is option: 'A'.

$\mathrm{LiOH}$ reacts with $\mathrm{CO}_{2}$ to form $\mathrm{Li}_{2} \mathrm{CO}_{3}$ (atomic mass of $\mathrm{Li}=7$ ). The amount of $\mathrm{CO}_{2}$ (in g) consumed by $1 \mathrm{~g}$ of LiOH is closest to

Solution

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