$\mathrm{MnO}_4^{-}$reacts with $\mathrm{A}^{\mathrm{x}+}$ to form $\mathrm{AO}_3^{-}, \mathrm{Mn}^{2+}$ and $\mathrm{O}_2$. One mole of $\mathrm{MnO}_4^{-}$oxidizes 1.25 moles of $\mathrm{A}^{\mathrm{x}+}$ to $\mathrm{AO}_3^{-}$. What is the value of $\mathrm{x}$ ?

• Correct answer
  A

  1
• B

  3
• C

  4
• D

  2

Hence, the correct answer is option: 'A'.