$\mathrm{XeF}_4$ reacts with $\mathrm{SbF}_5$ to form an adduct $\left[\mathrm{XeF}_3\right]^{+}\left[\mathrm{SbF}_6\right]^{-}$. The shape/geometry around the Xe and Sb ions, in the adduct, are respectively

• A

  Pyramidal & Octahedral.
• B

  Trigonal & Octahedral.
• C

  Trigonal & Trigonal bipyramidal.
• Correct answer
  D

  T-Shaped & Octahedral.

Hence, the correct answer is option: 'D'.