Q118 / 120 · VITEEE 2011 · Physics
Polarising angle for water is $53^{\circ} 4^{\prime}$. If light is incident at this angle on the surface of water and reflected the angle of refraction is
- A$53^{\circ} 4^{\prime}$
- B$126^{\circ} 56^{\prime}$
- Correct answerC$36^{\circ} 56$
- D$30^{\circ} 4^{\prime}$
Solution
$$
\begin{array}{l}
\text { Here, } \theta p+r=90^{\circ} \\
\Rightarrow \quad r=90^{\circ}-\theta p \\
\text { or } \quad r=90^{\circ}-53^{\circ} 4^{\prime}=36^{\circ} 56
\end{array}
$$
Hence, the correct answer is option: 'C'.