Q23 / 90 · JEE Main 2024 (29 Jan Shift 2) · Chemistry

Phenol treated with chloroform in presence of sodium hydroxide, which further hydrolysed in presence of an acid results

A
Salicyclic acid
B
Benzene-1,2-diol
C
Benzene-1, 3-diol
Correct answer
D
2-Hydroxybenzaldehyde

Solution

Chloroform $({CHCl}_{3})$ in the presence of an alkali $(NaOH)$ undergoes formylation of phenol at the ortho-position. This is also called as the Reimer-Tiemann reaction.

Hence, the answer is option D.

Hence, the correct answer is option: 'D'.

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