Q18 / 54 · JEE Advanced 2017 (Paper 2) · Chemistry
Paragraph:
The reaction of compound $\mathbf{P}$ with $\mathrm{CH}_{3} \mathrm{MgBr}$ (excess) in $\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{O}$ followed by addition of $\mathrm{H}_{2} \mathrm{O}$ gives $\mathbf{Q}$. The compound $\mathbf{Q}$ on treatment with $\mathrm{H}_{2} \mathrm{SO}_{4}$ at $0^{\circ} \mathrm{C}$ gives $\mathbf{R}$. The reaction of $\mathbf{R}$ with $\mathrm{CH}_{3} \mathrm{COCl}$ in the presence of anhydrous $\mathrm{AlCl}_{3}$ in $\mathrm{CH}_{2} \mathrm{Cl}_{2}$ followed by treatment with $\mathrm{H}_{2} \mathrm{O}$ produces compound $\mathbf{S}$. [Et in compound $\mathbf{P}$ is ethyl group]

Question:
The product $\mathbf{S}$ is

Question: The product $\mathbf{S}$ is
- A

- B

- C

- Correct answerD

Hence, the correct answer is option: 'D'.