Q45 / 120 · NDA 2024 (Phase 2) · Mathematics

Paragraph: Let $(8+3 \sqrt{7})^{20}=\mathrm{U}+\mathrm{V}$ and $(8-3 \sqrt{7})^{20}=\mathrm{W}$, where U is an integer and $0 < \mathrm{V} < 1$.
Question: What is $\mathrm{V}+\mathrm{W}$ equal to?

  • A
    $8$
  • B
    $4$
  • C
    $2$
  • Correct answer
    D
    $1$

Solution

We have, $(8+3 \sqrt{7})^{20}=\mathrm{U}+\mathrm{V}$....(i) and $(8-3 \sqrt{7})^{20}=\mathrm{W}$....(ii) Here, $\mathrm{o} < \mathrm{W} < 1$ Now, adding equation (i) \& (ii), we have, $\begin{aligned} & \mathrm{U}+\mathrm{V}+\mathrm{W}=(8+3 \sqrt{7})^{20}+(8-3 \sqrt{7})^{20} \\ & =2\left[{ }^{20} \mathrm{C}_0 \cdot 8^{20}+{ }^{20} \mathrm{C}_2 8^{18} \cdot(3 \sqrt{7})^2+\ldots .+(3 \sqrt{7})^{20}\right] \end{aligned}$ R.H.S. is an even number. Also, $\mathrm{o} < \mathrm{V} < 1, \mathrm{o} < \mathrm{W} < 1$ and U is an integer $\Rightarrow \mathrm{V}+\mathrm{W}$ is an integer $\Rightarrow \mathrm{V}+\mathrm{W}=1$ So, $V+W=1$

Hence, the correct answer is option: 'D'.

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