Q36 / 66 · JEE Advanced 2007 (Paper 2) · Mathematics

Paragraph: If a continuous $f$ defined on the real line $R$, assume positive and negative values in $R$, then the equation $f(x)=0$ has a root in $R$. For example, if it is known that a continuous function $f$ on $R$ is positive at some point and its minimum values is negative, then the equation $f(x)=0$ has a root in $R$. Consider $f(x)=k e^x-x$ for all real $x$, where $k$ is real constant.Question: The line $y=x$ meets $y=k e^x$ for $k \leq 0$ at

  • A
    no point
  • Correct answer
    B
    one point
  • C
    two points
  • D
    more than two points

Solution

$$ \text { Let } y=x \text { intersect the curve } y=k e^x \text { at exactly one point when } k \leq 0 \text {. } $$ Figure

Hence, the correct answer is option: 'B'.

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