Q33 / 54 · JEE Advanced 2016 (Paper 2) · Mathematics

Paragraph: Football teams $T_{1}$ and $T_{2}$ have to play two games against each other. It is assumed that the outcomes of the two games are independent. The probabilities of $T_{1}$ winning, drawing and losing a game against $T_{2}$ are $\frac{1}{2}, \frac{1}{6}$ and $\frac{1}{3}$, respectively. Each team gets $3$ points for a win, $1$ point for a draw and $0$ point for a loss in a game. Let $X$ and $Y$ denote the total points scored by teams $T_{1}$ and $T_{2}$, respectively, after two games.
Question: $P(X>Y)$ is

  • A
    14
  • Correct answer
    B
    512
  • C
    12
  • D
    712

Solution

PX>Y=PT1 win PT1win+PT1win Pmatch draw+Pmatch draw. PT1win
=12×12+12×16+16×12=512

Hence, the correct answer is option: 'B'.

Relevant Questions