Q10 / 160 · TS EAMCET 2020 (10 Sep Shift 1) · Chemistry

$\mathrm{KMnO}_4$ oxidises $\mathrm{C}_2 \mathrm{H}_2 \mathrm{O}_4$ to form $\mathrm{CO}_2$. In which of the following, the reaction will be faster?

  • Correct answer
    A
    Aq. HCl solution
  • B
    Aq. $\mathrm{NaOH}$ solution
  • C
    Aq. $\mathrm{NaCl}$ solution
  • D
    Aq. $\mathrm{NaHCO}_3$ solution

Solution

The reaction will faster in aqueous $\mathrm{HCl}$ because chlorine ion present in $\mathrm{HCl}$ get oxidised into chlorine gas by $\mathrm{KMnO}_4$, so the amount of $\mathrm{KMnO}_4$ will be more as it oxidises both oxalic acid and chlorine ion when $\mathrm{HCl}$ is present.

Hence, the correct answer is option: 'A'.

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