Optically active
was found to have lost its optical activity after standing in water containing a few drops of acids, mainly due to the formation of

• A

  $\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}=\mathrm{CH}_2$
• Correct answer
  B

  $\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_3$
• C

  
  
• D

  $\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{OH}$

Solution

The above optically active compound undergo dehydration with few drops of acid and form stable alkene through the formation of stable carbocation.

Hence, the correct answer is option: 'B'.