Only 2% of the optical source frequency is the available channel bandwidth for an optical communicating system operating at 1000 nm. If an audio…

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Only 2% of the optical source frequency is the available channel bandwidth for an optical communicating system operating at 1000 nm. If an audio signal requires a bandwidth of 8kHz, how many channels can be accommodated for transmission

MARKS Content Team · Accepted Answer

Correct answer: (B) 75×10^7. Frequency f=c/(λ)=(3×10^8)/(1000×10^(-9))=3×10^14 Hz Band width used for transmission =2/100×3×10^14 Hz=6×10^12 Hz Number of channels N=(Total bandwidth of channel )/(Bandwidth needed per channel )=(6×10^12)/(8×10^3)=600/8×10^7=75×10^7

Only $2 %$ of the optical source frequency is the available channel bandwidth for an optical communicating system operating at $1000 nm$ . If an audio signal requires a bandwidth of $8 kHz$ , how many channels can be accommodated for transmission

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