One of the following values of inputs $\mathrm{A}, \mathrm{B}$ and C respectively gives output $(\mathrm{Y})$ of the following combination of logic gates as ' 1 ' is

The circuit's output $Y$ represents the logical AND of input $A$ with the OR of inputs $B$ and $C$, expressed as $Y = A \cdot (B + C)$.

For $Y$ to be $1$, both conditions $A = 1$ and $B + C = 1$ must hold true. The OR condition $B + C = 1$ requires at least one of $B$ or $C$ to be $1$.

Evaluating the options: only choice D, with $A=1$, $B=0$, $C=1$, satisfies both $A = 1$ and $B + C = 1$ since $0 + 1 = 1$, leading to $Y = 1 \cdot 1 = 1$.

The correct input combination is $\boxed{\text{D}}$.