Q18 / 90 · JEE Main 2023 (11 Apr Shift 2) · Chemistry

One mole of $P_{4}$ reacts with $8$ moles of ${SOCl}_{2}$ to give $4$ moles of $A$ , $x$ mole of ${SO}_{2}$ and $2$ moles of $B$ . $A, B$ and $x$ respectively are

A
${POCl}_{3}, S_{2} {Cl}_{2}$ and $2$
Correct answer
B
${PCl}_{3}, S_{2} {Cl}_{2}$ and $4$
C
${PCl}_{3}, S_{2} {Cl}_{2}$ and $2$
D
${POCl}_{3}, S_{2} {Cl}_{2}$ and $4$

Solution

Thionyl chloride reacts with white phosphorus to produce phosphorus trichloride. The other side products in this reaction are sulphur dioxide and Sulphur monochloride.

$P_{4} + 8 {SOCl}_{2} \to 4 {PCl}_{3} + 4 {SO}_{2} + 2 S_{2} {Cl}_{2}$
Hence $A = {PCl}_{3}, x = 4, B = S_{2} {Cl}_{2}$

Hence, the correct answer is option: 'B'.

One mole of P4 reacts with 8 moles of SOCl2 to give 4 moles of A, x mole of SO2 and 2 moles of B. A, B and x respectively are

Solution

Relevant Questions

One mole of $P_{4}$ reacts with $8$ moles of ${SOCl}_{2}$ to give $4$ moles of $A$ , $x$ mole of ${SO}_{2}$ and $2$ moles of $B$ . $A, B$ and $x$ respectively are