Q15 / 200 · AP EAMCET 2002 · Chemistry

One mole of fluorine is reacted with two moles of hot concentrated $\mathrm{KOH}$. The products formed are $\mathrm{KF}, \mathrm{H}_2 \mathrm{O}$ and $\mathrm{O}_2$. The molar ratio of $\mathrm{KF}, \mathrm{H}_2 \mathrm{O}$ and $\mathrm{O}_2$, respectively is

  • A
    $1: 1: 2$
  • Correct answer
    B
    $2: 1: 0.5$
  • C
    $1: 2: 1$
  • D
    $2: 1: 2$

Solution

Stoichiometric equation for the reaction is $$ \mathrm{F}_2+2 \mathrm{KOH} \longrightarrow 2 \mathrm{KF}+\mathrm{H}_2 \mathrm{O}+\frac{1}{2} \mathrm{O}_2 $$

Hence, the correct answer is option: 'B'.

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