Q64 / 90 · JEE Main 2019 (10 Apr Shift 2) · Physics

One mole of an ideal gas passes through a process where pressure and volume obey the relation  P=Po1-12VoV2 . Here Po and Vo are constants. Calculate the change in the temperature of the gas if its volume changes from Vo  to  2Vo .

  • A
    14P0V0R
  • Correct answer
    B
    54P0V0R
  • C
    12P0V0R
  • D
    34P0V0R

Solution

For ideal gas, PV=nRT
Therefore, nRTV=P01-12V0V2
⇒ T=P0VR1-12V0V2
Therefore, the change in temperature is:
ΔT=Tf-Ti
=P02V0R1-12V02V02-P0VR1-V022V02
=5P0V04R

Hence, the correct answer is option: 'B'.

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