One gram of hydrogen and 112 g of nitrogen are enclosed in two separate containers each of volume 5 L and at 27°C . If the pressure of the hydrogen is…

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One gram of hydrogen and 112 g of nitrogen are enclosed in two separate containers each of volume 5 L and at 27°C . If the pressure of the hydrogen is 1 atm, then the pressure of nitrogen would be

MARKS Content Team · Accepted Answer

Correct answer: (C) 8 atm. Mol of H_2=1/(2 )mol Mol of N_2=(112 g)/(28 gmol^(-1))=4 mol p_1V=n_1RT (Constant T and V) p_2V=n_2RT So p_1/p_2=n_1/n_2 i.e., (1 atm)/p_2=1/2 mol4 mol Hence, p_2=8 atm.

One gram of hydrogen and 112 g of nitrogen are enclosed in two separate containers each of volume 5 L and at $27 ° C$ . If the pressure of the hydrogen is 1 atm, then the pressure of nitrogen would be

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