Q124 / 270 · NDA 2023 (Phase 1) · General Ability

One block of 2.0 kg mass is placed on top of another block of 3.0 kg mass. The coefficient of static friction between the two blocks is 0.2 . The bottom block is pulled with a horizontal force $F$ such that both the blocks move together without slipping. Taking acceleration due to gravity as $10 \mathrm{~m} / \mathrm{s}^2$, the maximum value of the frictional force is :

  • A
    50 N
  • B
    30 N
  • C
    4 N
  • Correct answer
    D
    10 N

Solution

Coefficient of static friction, $\mu=0.2$ Maximum frictional force, $\mathrm{f}_{\max }=\mu\left(\mathrm{m}_1+\mathrm{m}_2\right) \mathrm{g}$ $=0.2 \times(2+3) \times 10$ $=10 \mathrm{~N}$

Hence, the correct answer is option: 'D'.

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